Typically " ? " = 1 / 4, which yields the constant average acceleration method, is used.
3.
:It seems odd to ask for average acceleration, rather than average velocity, in a problem like this.
4.
It is a simplified version of Langevin dynamics and corresponds to the limit where no average acceleration takes place.
5.
:There is something else confusing about " average acceleration ", how to deal with negative acceleration ( deceleration ).
6.
The left hand side is this constant value of the acceleration and the right hand side is the average acceleration.
7.
Brownian dynamics can be considered as overdamped Langevin dynamics, i . e . Langevin dynamics where no average acceleration takes place.
8.
To reach a terminal speed of 12 km / s over a distance of 12km requires an average acceleration of 6 km / s 2-that's about 600 g.
9.
Once the particle is moving in the drift direction, the magnetic field deflects it back against the external force, so that the average acceleration in the direction of the force is zero.
10.
I suppose we can call the 1 g answer " the average of the absolute values of accelerations " and the 0 g answer " the average acceleration ", to avoid this confusion.
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